Mathematics - Permutation & Combination Question with Solution | TestHub
MathematicsPermutation & CombinationArrangement under ConstraintMedium2 minQB
MathematicsMediumsingle choice
Passage / Comprehension
Let S be the set of the first 18 positive integers.
The number of ways of selecting 3 numbers from S such that either they are all consecutive or no two of them are consecutive is
Options:
Answer:
B
Solution:
Number of ways of selecting 3 numbers which are consecutive = 16 Number of ways of selecting 3 numbers no two of which are consecutive =
Stream:JEESubject:MathematicsTopic:Permutation & CombinationSubtopic:Arrangement under Constraint
⏱ 2mℹ️ Source: QB
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