Mathematics - Permutation & Combination Question with Solution | TestHub

MathematicsPermutation & CombinationGroup formationMedium2 minQB

MathematicsMediummultiple choice

Number of ways of giving away 10 different gifts to 5 students so that each get atleast one gift and a particular student gets exactly 4 gifts

Answer:

B, C, D

Solution:

Number of ways $= 1 0_{C_{4}} (\frac{6 !}{2 ! 2 !} \times \frac{4 !}{2 ! 2 !} + \frac{6 !}{3 ! 3 !} \times 4!) = 327600$

Stream:JEESubject:MathematicsTopic:Permutation & CombinationSubtopic:Group formation

⏱ 2mℹ️ Source: QB

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