There are 2010 chairs round the table numbered from 1 to 2010.The numbers of ways in which 5 persons can be seated in any five of these chairs so that the number of empty chairs between any two consecutive persons must be same, is
Options:
Answer:
A
Solution:
$\frac{2010}{5} = 402$

Question

There are 2010 chairs round the table numbered from 1 to 2010.The numbers of ways in which 5 persons can be seated in any five of these chairs so that the number of empty chairs between any two consecutive persons must be same, is

Options:

Answer:

A

Solution:

$\frac{2010}{5} = 402$

TestHub · Accepted Answer

5 2010 ​ = 402

Mathematics - Permutation & Combination Question with Solution | TestHub

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