The number of arrangements of A 1 , A 2 … , A 10 in a line so that A 1 is always above than A 2 ,is

Mathematics - Permutation & Combination Question with Solution | TestHub

MathematicsPermutation & CombinationFundamental PrincipleEasy2 minQB

MathematicsEasysingle choice

The number of arrangements of $A_{1}, A_{2} \dots, A_{10}$ in a line so that $A_{1}$ is always above than $A_{2}$ ,is

Answer:

Solution:

Total number of arrangement in which $A_{1}$ is always above than $A_{2} = \frac{1}{2} (10!)$

Stream:JEESubject:MathematicsTopic:Permutation & CombinationSubtopic:Fundamental Principle

⏱ 2mℹ️ Source: QB

Loading discussions...