Mathematics - Permutation & Combination Question with Solution | TestHub

$1323000=2^3{3}^3{7}^2{5}^3$

$\mathrm{D}=2^{\mathrm{a}}{3}^{\mathrm{b}}{7}^{\mathrm{c}}{5}^{\mathrm{d}}$ then $a\ge 1,b\ge 1,c\ge 1,d\ge 1$ for any even divisor divisible by 105

Hence required ans are is $3\times 3\times 2\times 3=54$