Mathematics - Functions Question with Solution | TestHub

From the given condition, $\left\{\frac{x}{3}\right\}+\left\{\frac{3x}{2}\right\}+\left\{\frac{y}{2}\right\}+\left\{\frac{3y}{4}\right\}=0$ $\Rightarrow \frac{x}{3},\frac{3x}{2},\frac{y}{2},\frac{3y}{4}$ must be integers $\begin{array}{rlrl}& \therefore x=6,12,18,24& y=4,8,12,16,20,24,28& \therefore \text{ No. of order pairs }=4\times 7=28\end{array}$