Mathematics - Permutation & Combination Question with Solution | TestHub

MathematicsPermutation & CombinationDivision of Identical itemsEasy2 minQB

MathematicsEasysingle choice

If $a, b, c$ are three natural numbers in AP and $a + b + c = 21$ then the possible number of values of the ordered triplet ( $a, b, c$ ) is

Answer:

Solution:

$a + a + d + a + 2 d = 21$ or $a + d = 7$

$∴ a + c = 14$ and $b = 7$ .

The number of positive integral solutions of $(a + c = 14)$ is 13.

Stream:JEESubject:MathematicsTopic:Permutation & CombinationSubtopic:Division of Identical items

⏱ 2mℹ️ Source: QB

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