Mathematics - Permutation & Combination Question with Solution | TestHub

The girls sit together in $(1,2)$ or $(2,3)\dots \dots$ seated in $2\times 13=26$ ways

If one boy sits between the girls they can be seated in $2\times 12=24$ ways

If two boy sits between the girls they can be seated in $2\times 12=24$ ways

The desired number is $14!-(26+24+22)12!=110.12!$