Mathematics - Permutation & Combination Question with Solution | TestHub
MathematicsPermutation & CombinationnPr & nCrEasy2 minQB
MathematicsEasysingle choice
A student is to answer 10 out of 13 questions in an examination such that he must choose at least 4 from the first five question. The number of choices available to him is
Options:
Answer:
B
Solution:
Number of required ways
Stream:JEESubject:MathematicsTopic:Permutation & CombinationSubtopic:nPr & nCr
⏱ 2mℹ️ Source: QB
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