( 1 2 + 1 ) 1 ! + ( 2 2 + 1 ) 2 ! + ( 3 2 + 1 ) 3 ! + … . upto 15 terms =

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MathematicsSequence & SeriesMiscellaneous/MixedMedium2 minQB

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$(1^{2} + 1) 1! + (2^{2} + 1) 2! + (3^{2} + 1) 3! + \dots$ . upto 15 terms =

Answer:

Solution:

The equation is $T = (n^{2} + 1) n!$ .

$= [(n + 2) (n + 1) - 3 (n + 1) + 2] n!$

$= (n + 2)! - 3 (n + 1)! + 2 (n!)$

Stream:JEESubject:MathematicsTopic:Sequence & SeriesSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: QB

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