Mathematics - Permutation & Combination Question with Solution | TestHub

MathematicsPermutation & CombinationMiscellaneous/MixedEasy2 minQB

MathematicsEasysingle choice

The last digit of $(8217)^{1114}$ is

Answer:

Solution:

$7^{4 n + 1}$ ends in $7, 7^{4 n + 2}$ ends in $9, 7^{4 n + 3}$ ends in $3. 7^{4 n}$ ends in 1

Now $1114 = 4 \times 278 + 2$

Hence the last digit of $(8217)^{1114}$ is the same as the last digit of $7^{1114} =$ last digit of $7^{2} = 9$

Stream:JEESubject:MathematicsTopic:Permutation & CombinationSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: QB

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