Mathematics - Permutation & Combination Question with Solution | TestHub
MathematicsPermutation & CombinationArrangement under ConstraintMedium2 minQB
MathematicsMediumsingle choice
Passage / Comprehension
Let ‘S’ be the set of first 18 natural numbers. The number of ways of selecting from ‘S’
Three numbers such that they are all consecutive (or) no two of them are consecutive is
Options:
Answer:
A
Solution:
No. of ways of selecting 3 consecutive numbers = 16.
No. of ways of selecting 3 numbers such that no two are consecutive = 560.
Therefore, the required number of ways = .
Stream:JEESubject:MathematicsTopic:Permutation & CombinationSubtopic:Arrangement under Constraint
⏱ 2mℹ️ Source: QB
Doubts & Discussion
Loading discussions...
