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Mathematics - Permutation Combination Question with Solution | TestHub

MathematicsPermutation CombinationArrangement under ConstraintEasy2 minPYQ_2025

MathematicsEasynumerical

The number of ways, 5 boys and 4 girls can sit in a row so that either all the boys sit together or no two boys sit together, is -

Answer:

17280.00

Solution:

A : number of ways that all boys sit together $= 5! \times 5!$ B : number of ways if no 2 boys sit together $= 4! \times 5$ ! $A \cap B = ϕ$ Required no. of ways $= 5! \times 5! + 4! \times 5! = 17280$

Stream:JEESubject:MathematicsTopic:Permutation CombinationSubtopic:Arrangement under Constraint

⏱ 2mℹ️ Source: PYQ_2025

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