Mathematics - Permutation & Combination Question with Solution | TestHub

MathematicsPermutation & CombinationArrangement under ConstraintHard2 minPYQ_2023
MathematicsHardsingle choice

The number of five-digit numbers, greater than40000and divisible by5, which can be formed using the digits0, 1, 3, 5, 7and9without repetition, is equal to

Options:

Answer:
B
Solution:

We need to find the number of 5 digit numbers greater than 40000 and divisible by 5.

Case I : Numbers start with 5.

Here if the number starts with 5 it should end with 0 to be divisible by 5.

Case II : Number starts with 7 and the last digit can have 0 or 5.

Case III : The number starts with 9 and the last digit should have 0 or 5.

Total numbers =120.

Hence this is the correct option.

Stream:JEESubject:MathematicsTopic:Permutation & CombinationSubtopic:Arrangement under Constraint
2mℹ️ Source: PYQ_2023

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