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MathematicsPermutation & CombinationnPr & nCrHard2 minPYQ_2022
MathematicsHardnumerical

LetS=4,6,9andT=9,10,11,,1000. If
A=a1+a2++ak:kN,a1,a2,a3,,akSthen the sum of all the elements in the setT-Ais equal to _______.

Answer:
11.00
Solution:

Given,

S=4,6,9 & T=9,10,11..1000

Also given Aa1+a2+..+ak:KN & aiS

Now here by the definition of set 'A'

A=a:a=4x+6y+9z

Now checking number we will get from equation a=4x+6y+9z

Put x=y=0 & z=1 we get a=9

Put x=y=1 & z=0 we get a=10

Put x=0, y=2 & z=0 we get a=12

Put x=1, y=0 & z=1 we get a=13

Put x=2, y=1 & z=o we get a=14

Put x=0, y=1 & z=1 we get a=15

...

Put x=1, y=1 & z=1 we get a=19

Now from 20 onwards we get all number as all number will be of type 4k, 4k+1, 4k+2 & 4k+3 and from equation 1, 2 & 3 remainder get compensated by combination of  6y and 9z,

So, except the element 11, every element of set T is of the form 4x+6y+9z for some x,y,zW

T-A=11

Stream:JEESubject:MathematicsTopic:Permutation & CombinationSubtopic:nPr & nCr
2mℹ️ Source: PYQ_2022

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