Mathematics - Permutation & Combination Question with Solution | TestHub

MathematicsPermutation & CombinationnPr & nCrMedium2 minPYQ_2021

MathematicsMediumsingle choice

Team ${}^{'}A^{'}$ consists of $7$ boys and $n$ girls and Team ${}^{'}B^{'}$ has $4$ boys and $6$ girls. If a total of $52$ single matches can be arranged between these two teams when a boy plays against a boy and a girl plays against a girl, then $n$ is equal to:

Options:

Answer:

Solution:

Total matches between boys of both team $= {}^{7}C_{1} \times {}^{4}C_{1} = 28$

Total matches between girls of both team $= {}^{n}C_{1} \times {}^{6}C_{1} = 6 n$

Given, $28 + 6 n = 52$

$\Rightarrow n = 4$

Stream:JEESubject:MathematicsTopic:Permutation & CombinationSubtopic:nPr & nCr

⏱ 2mℹ️ Source: PYQ_2021

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