Two families with three members each and one family with four members are to be seated in a row. In how many ways can they be seated so that the same family members are not separated ?

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We will use the concept 'objects are together' 3 ! ⏟ Total 3 families × 3 ! 2 ⏟ families with all 3 members together × 4 ! ⏟ family with all 4 together = ( 3 ! ) 3 × 4 !

Mathematics - Permutation & Combination Question with Solution | TestHub

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