Mathematics - Permutation Combination Question with Solution | TestHub

MathematicsPermutation CombinationArrangement under ConstraintMedium2 minPYQ_2020

MathematicsMediumsingle choice

A person invites a party of 10 friends at dinner and place them so that 4 are on one round table and 6 on the other round table. The number of ways in which he can arrange the guests is

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Answer:

Solution:

Selection of 6 guests $= 10 C 6$ Permutation of 6 on round table $= 5!$ Permutation of 4 on round table $= 3!$ Then, total number of arrangements $= 10 C 6.5! .3!$ $= \frac{( 10 )!}{6 ! 4 !} \cdot 5! .3! = \frac{( 10 )!}{24}$

Stream:BITSATSubject:MathematicsTopic:Permutation CombinationSubtopic:Arrangement under Constraint

⏱ 2mℹ️ Source: PYQ_2020

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