Mathematics - Permutation & Combination Question with Solution | TestHub

MathematicsPermutation & CombinationnPr & nCrHard2 minPYQ_2015

MathematicsHardsingle choice

The number of ways of selecting $15$ teams from $15$ men and $15$ women, such that each team consists of a man and a woman is

Options:

Answer:

Solution:

First team can be selected in $(^{15} C_{1} .^{15} C_{1})$ way, second in $(^{14} C_{1} .^{14} C_{1})$ way and so on. So, number of ways of selecting $15$ teams $= \frac{{(15!)}^{2}}{15!} = (15!)$

Stream:JEESubject:MathematicsTopic:Permutation & CombinationSubtopic:nPr & nCr

⏱ 2mℹ️ Source: PYQ_2015

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