Mathematics - Permutation & Combination Question with Solution | TestHub

MathematicsPermutation & CombinationnPr & nCrMedium2 minPYQ_2012

MathematicsMediumsingle choice

Assuming the balls to be identical except for difference in colours, the number of ways in which one or more balls can be selected from $10$ white, $9$ green and $7$ black balls is

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Answer:

Solution:

Number of ways of selecting one or more balls from $10$ white, $9$ green, and $7$ black balls $= (10 + 1) (9 + 1) (7 + 1) - 1 = 11 \times 10 \times 8 - 1 = 879.$

Stream:JEESubject:MathematicsTopic:Permutation & CombinationSubtopic:nPr & nCr

⏱ 2mℹ️ Source: PYQ_2012

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