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Mathematics - Permutation & Combination Question with Solution | TestHub

MathematicsPermutation & CombinationnPr & nCrMedium2 minPYQ_2003
MathematicsMediumsingle choice

A student is to answer 10 out of 13 questions in an examination such that he must choose at least 4 from the first five questions. The number of choices available to him is

Options:

Answer:
C
Solution:

As for given question two cases are possible. (i) Selecting 4 out of first five question and 6 out of remaining 8 question choices. (ii) Selecting 5 out of first five question and 5 out of remaining 8 questions choices. Therefore, total number of choices .

Stream:JEESubject:MathematicsTopic:Permutation & CombinationSubtopic:nPr & nCr
2mℹ️ Source: PYQ_2003

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