Let A = [ 1 0 2 1 ] and B = I + adj ( A ) + ( adj A ) 2 + … + ( adj A ) 10 . Then, the sum of all the elements of the matrix B is:

B = [ 1 0 0 1 ] + [ 1 0 − 2 1 ] + [ 1 0 − 4 1 ] + … + [ 1 0 − 20 1 ] B = [ 11 0 − 110 11 ] ⇒ sum of elements of B = − 88

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MathematicsMatricesAdjointMedium2 minPYQ_2024

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Let $A = [1021]$ and $B = I + adj (A) + (adj A)^{2} + \dots + (adj A)^{10}$ . Then, the sum of all the elements of the matrix $B$ is:

Answer:

Solution:

$B = [1001] + [10 - 2 1] + [10 - 4 1] + \dots + [10 - 20 1] B = [110 - 110 11] \Rightarrow sum of elements of B = - 88$

Stream:JEESubject:MathematicsTopic:MatricesSubtopic:Adjoint

⏱ 2mℹ️ Source: PYQ_2024

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