Mathematics - Matrices Question with Solution | TestHub

MathematicsMatricesAdjointHard2 minQB

MathematicsHardsingle choice

Let invertible $A$ and $B$ be of order 3 , with $∣ B ∣ = 2$ and $A^{T} ∣ A ∣ B = A ∣ B ∣ B^{T}$ . Find $A B^{- 1} adj (A^{T} B)^{- 1}$ .

Answer:

Solution:

Taking determinants gives $∣ A ∣ = 2$ . The determinant of the required product is $1/ (∣ A ∣^{3} ∣ B ∣) = 1/16$ .

Stream:JEESubject:MathematicsTopic:MatricesSubtopic:Adjoint

⏱ 2mℹ️ Source: QB

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