The maximum value of z = 6 x + 8 y subject to constraints 2 x + y ≤ 30 , x + 2 y ≤ 24 and x ≥ 0 , y ≥ 0 is

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MathematicsLinear ProgrammingGeneralEasy2 minPYQ_2020

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The maximum value of $z = 6 x + 8 y$ subject to constraints $2 x + y \leq 30, x + 2 y \leq 24$ and $x \geq 0, y \geq 0$ is

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Here, $2 x + y \leq 30, x + 2 y \leq 24, x, y \geq 0$ The shaded region represents the feasible region, hence $z = 6 x + 8 y$ . Obviously it is maximum at (12,6) Hence $z = 12 \times 6 + 8 \times 6 = 120$

Stream:BITSATSubject:MathematicsTopic:Linear ProgrammingSubtopic:General

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