Consider 2 x + 4 y ≥ 1 and 3 x + 2 y ≤ 1 , x , y ≥ 0 . Then number of possible solutions are :

Mathematics - Linear Programming Question with Solution | TestHub

MathematicsLinear ProgrammingGeneralEasy2 minPYQ_2014

MathematicsEasysingle choice

Consider $\frac{x}{2} + \frac{y}{4} \geq 1$ and $\frac{x}{3} + \frac{y}{2} \leq 1, x, y \geq 0$ . Then number of possible solutions are :

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Solution:

Consider $\frac{x}{2} + \frac{y}{4} \geq 1, \frac{x}{3} + \frac{y}{2} \leq 1$ , x, $y \geq 0$ convert them into equation and solve them and draw the graph of these equations we get $y = 1$ and $x = 3/2$
From graph region is finite but numbers of possible solutions are infinite because for different values of $x$ and $y$ we have different or infinite no. of solutions.

Stream:BITSATSubject:MathematicsTopic:Linear ProgrammingSubtopic:General

⏱ 2mℹ️ Source: PYQ_2014

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