Mathematics - Limits Question with Solution | TestHub

If $f(0)=0$ and that ' $f$ ' is differentiable at $\mathrm{x}=0$, and ' k ' is a positive integer. Then

${\mathrm{lt}}_{x\to 0}\frac{1}{x}\left[f(x)+f\left(\frac{x}{2}\right)+f\left(\frac{x}{3}\right)+---+f\left(\frac{x}{k}\right)\right]$