For x > 0 ; lim x → 0 { ( sin x ) 1/ x + ( x 1 ) s i n x } is ____

x → 0 Lt ( sin x ) 1/2 = 0 ( 0 < sin x < 1 ; x 1 → ∞ ) And lo g y = sin x . lo g x

Mathematics - Limits Question with Solution | TestHub

MathematicsLimitsMiscellaneous/MixedMedium2 minQB

MathematicsMediumsingle choice

For $x > 0; lim_{x \to 0} {(sin x)^{1/ x} + (\frac{1}{x})^{s i n x}}$ is $____$

Answer:

Solution:

$x \to 0 Lt (sin x)^{1/2} = 0 (0 < sin x < 1; \frac{1}{x} \to \infty)$ And $lo g y = sin x . lo g x$

Stream:JEESubject:MathematicsTopic:LimitsSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: QB

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