Mathematics - Limits Question with Solution | TestHub

If $\pi =3.14$, then $[-{\pi }^2]=-10$.

$${\mathrm{Lt}}_{x\to 0}\frac{\tan ([-{\pi }^2]x^2)-\tan ([-{\pi }^2])x^2}{{\sin }^{2}x}$$

Diluting by $x^2$, we get:

$${\mathrm{Lt}}_{x\to 0}\frac{\frac{-\tan (10x^2)}{x^2}+\tan (10)}{\frac{{\sin }^{2}x}{x^2}}=\tan (10)-10$$