Mathematics - Limits Question with Solution | TestHub

If $\mathrm{f}(\mathrm{x})=0$ be a quadratic equation such that $f(-\pi )=f(\pi )=0$ and $f\left(\frac{\pi }{2}\right)=\frac{-3{\pi }^2}{4}$, then ${\lim }_{x\to -\pi }\frac{f(x)}{\sin (\sin x)}$ is equal to