Mathematics - Limits Question with Solution | TestHub

${\lim }_{x\to 0^{-}}f(x)={\lim }_{h\to 0}\sqrt{\{-h\}\cot \{-h\}}$ $={\lim }_{h\to 0}\sqrt{(1-h)\cot (1-h)}=\sqrt{\cot 1}$ ${\lim }_{x\to 0^{+}}f(x)={\lim }_{h\to 0}\frac{{\tan }^2\{h\}}{h^2-[h{]}^2}={\lim }_{h\to 0}\frac{{\tan }^{2}h}{h^2}=1$ $\therefore {\lim }_{x\to 0}f(x)$ does not exist.