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MathematicsLimits1 power infinty basedEasy2 minPYQ_2023
MathematicsEasysingle choice

limt011sin2t+21sin2t+31sin2t......n1sin2tsin2tis equal to

Options:

Answer:
B
Solution:

L=limt011sin2t+21sin2t+31sin2t......n1sin2tsin2t

=limt01cosec2t+2cosec2t+3cosec2t......ncosec2tsin2t

=limt0  nsin2tsin2t1ncosec2t+2ncosec2t+3ncosec2t......1sin2t

=nlimt0  0+0+0......10=n

Stream:JEESubject:MathematicsTopic:LimitsSubtopic:1 power infinty based
2mℹ️ Source: PYQ_2023

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