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Mathematics - Limits Question with Solution | TestHub

MathematicsLimitsTrigonometric and Inverse Trigonometric limitsEasy2 minPYQ_2019
MathematicsEasysingle choice

limx0 sin2x2-1+cosxequals

Options:

Answer:
A
Solution:

limx0 sin2x2-1+cosx

On Rationalisation, we get,

     =limx0 sin2x2-1+cosx×2+1+cosx2+1+cosx

=limx0 2sinx2cosx221-cosx×2+1+cosx

=limx0 4sin2x2cos2x22sin2x2×2+1+cosx

=limx0 2cos2x22+1+cosx=2×22

=42.

Stream:JEESubject:MathematicsTopic:LimitsSubtopic:Trigonometric and Inverse Trigonometric limits
2mℹ️ Source: PYQ_2019

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