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MathematicsLimitsMiscellaneous/MixedMedium2 minPYQ_2018
MathematicsMediumnumerical

For each positive integern, letyn=1n((n+1)(n+2)...(n+n))1n. Iflimnyn=L,then the value ofL(wherexis the greatest integer less than or equal tox) is ____

Answer:
1.00
Solution:

yn=1+1n1+2n.1+nn1n
yn=r=1n1+rn1n
lnyn=1nr=1nln1+rn
  limnln(yn)=limnr=1n1nln1+rn
 lnL=01ln1+xdx
 lnL=ln4e
  L=4e
L=1

Stream:JEE_ADVSubject:MathematicsTopic:LimitsSubtopic:Miscellaneous/Mixed
2mℹ️ Source: PYQ_2018

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