If f ( x ) = { x 2 + 2 x − 15 x 2 + 3 x − 10 a , , when x  = − 5 when x = − 5 is continuous at x = − 5 , then the value of 'a' will be

lim x → − 5 f ( x ) = ( x + 5 ) ( x − 3 ) ( x − 2 ) ( x + 5 ) = − 8 − 7 = 8 7

Mathematics - Limits Question with Solution | TestHub

MathematicsLimitsAlgebraic and Rational LimitsEasy2 minPYQ_2013

MathematicsEasysingle choice

If $f (x) = {\frac{x ^{2} + 3 x - 10}{x ^{2} + 2 x - 15} a,, when x \neq = - 5 when x = - 5$ is continuous at $x = - 5$ , then the value of 'a' will be

Options:

Answer:

Solution:

$lim_{x \to - 5} f (x) = \frac{( x - 2 ) ( x + 5 )}{( x + 5 ) ( x - 3 )} = \frac{- 7}{- 8} = \frac{7}{8}$

Stream:BITSATSubject:MathematicsTopic:LimitsSubtopic:Algebraic and Rational Limits

⏱ 2mℹ️ Source: PYQ_2013

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