Two tangents PQ and PR drawn to the circle x 2 + y 2 − 2 x − 4 y − 20 = 0 from point P ( 16 , 7 ) . Ifthe centre of the circle is C then the area of quadrilateral PQCR is

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Area PQCR = 2 △ PQC = 2 × 2 1 ​ L × r where L = length of tangent and r = radius of circle. L = S 1 ​ ​ = 15 and r = 1 + 4 + 20 ​ = 5 Hence the required area = 75 sq. units.

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