Let f 1 ( x ) = sin − 1 ( cos ( sin 2 x ) ) , f 2 ( x ) = cos − 1 ( sin ( cos 2 x ) ) , f 3 ( x ) = sin − 1 ( cos ( cos 2 x ) ) , f 4 ( x ) = cos − 1 ( sin ( sin 2 x ) ) then

Question

Let f 1 ​ ( x ) = sin − 1 ( cos ( sin 2 x ) ) , f 2 ​ ( x ) = cos − 1 ( sin ( cos 2 x ) ) , f 3 ​ ( x ) = sin − 1 ( cos ( cos 2 x ) ) , f 4 ​ ( x ) = cos − 1 ( sin ( sin 2 x ) ) then

TestHub · Accepted Answer

Clearly, f 1 ​ ( x ) = 2 π ​ − sin 2 x ​ f 2 ​ ( x ) = 2 π ​ − cos 2 x ​ f 3 ​ ( x ) = 2 π ​ − cos 2 x ​ f 4 ​ ( x ) = 2 π ​ − sin 2 x ​

Mathematics - Inverse Trigonometric Functions Question with Solution | TestHub

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Doubts & Discussion

JEE Main + Advanced (1 year 12th class)

JEE Advanced (2028)