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Mathematics - Inverse Trigonometric Functions Question with Solution | TestHub

MathematicsInverse Trigonometric FunctionsT inverse T propertyMedium2 minQB

MathematicsMediumsingle choice

For -1≤x<0, evaluate $cos^{- 1} (2 x^{2} - 1) - 2 sin^{- 1} x$ .

Options:

Answer:

Solution:

Since $cos^{- 1} x \in (π /2, π], cos^{- 1} (2 x^{2} - 1) = 2 π - 2 cos^{- 1} x . S u b t r a c t in g 2 sin^{- 1} x an d u s in g cos^{- 1} x + sin^{- 1} x = π /2 l e a v es π .$

Stream:JEESubject:MathematicsTopic:Inverse Trigonometric FunctionsSubtopic:T inverse T property

⏱ 2mℹ️ Source: QB

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