tan − 1 ( 4 1 ) + tan − 1 ( 9 2 ) is equal to

tan − 1 ( 4 1 ) + tan − 1 ( 9 2 ) = tan − 1 { 1 − 4 1 × 9 2 4 1 + 9 2 } = tan − 1 { 36 − 2 9 + 8 } = tan − 1 ( 2 1 )

Mathematics - Inverse Trigonometric Functions Question with Solution | TestHub

MathematicsInverse Trigonometric FunctionsSum And Difference Of AnglesEasy2 minPYQ_2023

MathematicsEasysingle choice

$tan^{- 1} (\frac{1}{4}) + tan^{- 1} (\frac{2}{9})$ is equal to

Options:

Answer:

Solution:

$tan^{- 1} (\frac{1}{4}) + tan^{- 1} (\frac{2}{9}) = tan^{- 1} {\frac{\frac{1}{4} + \frac{2}{9}}{1 - \frac{1}{4} \times \frac{2}{9}}}$
$= tan^{- 1} {\frac{9 + 8}{36 - 2}} = tan^{- 1} (\frac{1}{2})$

Stream:BITSATSubject:MathematicsTopic:Inverse Trigonometric FunctionsSubtopic:Sum And Difference Of Angles

⏱ 2mℹ️ Source: PYQ_2023

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