The number of real solutions of Tan − 1 x ( x + 1 ) + Sin − 1 x 2 + x + 1 = 2 π is ____

Cos − 1 x 2 + x + 1 1 + Sin − 1 x 2 + x + 1 = 2 π ⇒ x 2 + x + 1 = 1

Mathematics - Inverse Trigonometric Functions Question with Solution | TestHub

MathematicsInverse Trigonometric FunctionsProperties of ITFEasy2 minQB

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The number of real solutions of $Tan^{- 1} x (x + 1) + Sin^{- 1} x^{2} + x + 1 = \frac{π}{2}$ is $____$

Answer:

Solution:

$Cos^{- 1} \frac{1}{x ^{2} + x + 1} + Sin^{- 1} x^{2} + x + 1 = \frac{π}{2} \Rightarrow x^{2} + x + 1 = 1$

Stream:JEESubject:MathematicsTopic:Inverse Trigonometric FunctionsSubtopic:Properties of ITF

⏱ 2mℹ️ Source: QB

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