Mathematics - Inverse Trigonometric Functions Question with Solution | TestHub

MathematicsInverse Trigonometric FunctionsIdentities, eqations and inequations involving ITFMedium2 minQB

MathematicsMediumsingle choice

$sin^{- 1} (sin 5) > x^{2} - 4 x$ holds if

Answer:

Solution:

$∴ \frac{3 π}{2} < 5 < \frac{5 π}{2} ∴ sin^{- 1} (sin 5) = 5 - 2 π$

Given

$\Rightarrow x^{2} - 4 x + (2 π - 5) < 0$

Roots of $x^{2} - 4 x + 2 π - 5 = 0$ are $2 \pm 9 - 2 π$

$∴ x^{2} - 4 x + 2 π - 5 < 0$

$\Rightarrow 2 - 9 - 2 π < x < 2 + 9 - 2 π$

Stream:JEESubject:MathematicsTopic:Inverse Trigonometric FunctionsSubtopic:Identities, eqations and inequations involving ITF

⏱ 2mℹ️ Source: QB

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