tan − 1 ( 4 1 ) + tan − 1 ( 9 2 ) equal to-

tan − 1 ( 4 1 ) + tan − 1 ( 9 2 ) = tan − 1 [ 1 − 4 1 × 9 2 4 1 + 9 2 ] = tan − 1 [ 2 1 ]

Mathematics - Inverse Trigonometric Function Question with Solution | TestHub

MathematicsInverse Trigonometric FunctionProperties of ITFEasy2 minPYQ_2012

MathematicsEasysingle choice

$tan^{- 1} (\frac{1}{4}) + tan^{- 1} (\frac{2}{9})$ equal to-

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Solution:

$tan^{- 1} (\frac{1}{4}) + tan^{- 1} (\frac{2}{9})$ $= tan^{- 1} [\frac{\frac{1}{4} + \frac{2}{9}}{1 - \frac{1}{4} \times \frac{2}{9}}] = tan^{- 1} [\frac{1}{2}]$

Stream:BITSATSubject:MathematicsTopic:Inverse Trigonometric FunctionSubtopic:Properties of ITF

⏱ 2mℹ️ Source: PYQ_2012

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