If ∫ ( x − 3 ) ( x − 5 ) 3 x + 1 d x = ∫ ( x − 3 ) − 5 d x + ∫ ( x − 5 ) B d x then the value of B is

We have, ( x − 3 ) ( x − 5 ) 3 x + 1 = x − 3 − 5 + x − 5 B 3 x + 1 = − 5 ( x − 5 ) + B ( x − 3 ) Put x = 5 3 ( 5 ) + 1 = B ( 5 − 3 ) 16 = 2 B or B = 8

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MathematicsIndefinite IntegrationPartial fractionEasy2 minPYQ_2021

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If $\int \frac{3 x + 1}{( x - 3 ) ( x - 5 )} d x = \int \frac{- 5}{( x - 3 )} d x + \int \frac{B}{( x - 5 )} d x$ then the value of $B$ is

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We have, $\frac{3 x + 1}{( x - 3 ) ( x - 5 )} = \frac{- 5}{x - 3} + \frac{B}{x - 5} 3 x + 1 = - 5 (x - 5) + B (x - 3) Put x = 5 3 (5) + 1 = B (5 - 3) 16 = 2 B or B = 8$

Stream:BITSATSubject:MathematicsTopic:Indefinite IntegrationSubtopic:Partial fraction

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