TestHub
TestHub

Mathematics - Indefinite Integration Question with Solution | TestHub

MathematicsIndefinite IntegrationSubstitutionMedium2 minPYQ_2019
MathematicsMediumsingle choice

For,x2nπ+1, nN(the set of natural numbers), the integralx2sinx2-1-sin2x2-12sinx2-1+sin2x2-1dx, is equal to
(wherecis a constant of integration).

Options:

Answer:
D
Solution:

I=x2sinx2-1-sin2x2-12sinx2-1+sin2x2-1dx

Let,x2-1=θxdx=12dθ

I=122sinθ-sin2θ2sinθ+sin2θdθ

=122sinθ-2sinθcosθ2sinθ+2sinθcosθdθ

=121-cosθ1+cosθdθ

=12tanθ2dθ

=12logesecθ212+c, wherecis the constant of integration.

=logesec2x2-12+c

Stream:JEESubject:MathematicsTopic:Indefinite IntegrationSubtopic:Substitution
2mℹ️ Source: PYQ_2019

Doubts & Discussion

Loading discussions...