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Mathematics - Indefinite Integration Question with Solution | TestHub

MathematicsIndefinite IntegrationSubstitutionHard2 minPYQ_2019
MathematicsHardsingle choice

Letα(0,π2) , be constant.If the integraltanx+tanαtanx-tanαdx=Axcos2α+Bxsin2α+C, where C is a constant of integration, then the functionsA(x)andB(x)are respectively

Options:

Answer:
A
Solution:

I=tanx+tanαtanx-tanαdx=sinxcosx+sinαcosαsinxcosx-sinαcosαdx
=sinxcosα+cosxsinαsinxcosα-cosxsinαdx=sinx+αsinx-αdx
=sinx-α+2αsin(x-α)dx=sinx-αcos2α+cosx-αsin2αsin(x-α)dx
=cos2α+sin2αcotx-αdx
=xcos2α+sin2αlogesinx-α+C
=(x-α)cos2α+sin2αlogesinx-α+C
Hence,Ax=x-αandBx=logesinx-α

Stream:JEESubject:MathematicsTopic:Indefinite IntegrationSubtopic:Substitution
2mℹ️ Source: PYQ_2019

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