Mathematics - Hyperbola Question with Solution | TestHub

MathematicsHyperbolaTangent to hyperbolaMedium2 minQB

MathematicsMediumnumerical

The slope of a common tangent to $x^{2} /16 - y^{2} /9 = 1$ and $y^{2} /16 - x^{2} /9 = 1$ is $m$ . Find $∣ m ∣$ .

Answer:

1.00

Solution:

Equating the tangent constants gives $16 m^{2} - 9 = - 9 m^{2} + 16$ , hence $m^{2} = 1$ . \end{document}

Stream:JEESubject:MathematicsTopic:HyperbolaSubtopic:Tangent to hyperbola

⏱ 2mℹ️ Source: QB

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