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Mathematics - Hyperbola Question with Solution | TestHub

MathematicsHyperbolaGeneralEasy2 minPYQ_2024
MathematicsEasysingle choice

For 0<θ<π/2, if the eccentricity of the hyperbola x2y2cosec2θ=5 is 7 times eccentricity of the ellipse x2cosec2θ+y2=5, then the value of θ is:

Options:

Answer:
C
Solution:

Given:

The equation of hyperbola is, x2-y2cosec2θ=5

x25-y25sin2θ=1 

And the equation of ellipse is x2cosec2θ+y2=5

x25sin2θ+y25=1 here a<b as sin2θ1

So, eH=1+sin2θ & eE=1-sin2θ

Also given, eH=7eE

1+sin2θ =71-sin2θ

1+sin2θ =7-7sin2θ

8sin2θ =6

sinθ =32

θ=π3

Stream:JEESubject:MathematicsTopic:HyperbolaSubtopic:General
2mℹ️ Source: PYQ_2024

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