A BC is a triangular park with A B = A C = 100 m . A TV tower stands at the mid-point of BC . The angles of elevation of the top of the tower at A , B , C are 4 5 ∘ , 6 0 ∘ , 6 0 ∘ respectively. The h

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A BC is a triangular park with A B = A C = 100 m . A TV tower stands at the mid-point of BC . The angles of elevation of the top of the tower at A , B , C are 4 5 ∘ , 6 0 ∘ , 6 0 ∘ respectively. The height of the tower is

TestHub · Accepted Answer

According to question, Let D E = h and C D = D B = x In △ EB D , tan 6 0 ∘ = x h ​ ⇒ x = 3 ​ h ​ Now, in △ A D E ​ tan 4 5 ∘ = D A E D ​ ⇒ D A = h ​ In △ A B D , by applying Pythagoras theorem ​ ⇒ ( 3 ​ h ​ ) 2 + h 2 = 10 0 2 ⇒ 3 4 h 2 ​ = 10000 ⇒ h = 50 3 ​ ​

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