Mathematics - Functions Question with Solution | TestHub

MathematicsFunctionsGeneral (Definition,type and special type)Medium2 min

MathematicsMediumsingle choice

Let $f : R \to R$ be a function defined by $f (x) = [x]^{2} + [x + 1] - 3$ {where $[.]$ is G.I.F.}, then $f (x)$ is

Answer:

Solution:

$f (x) = [x]^{2} + [x + 1] - 3$ $= [x]^{2} + [x] - 2$ let $t = [x] \Rightarrow t \in I$ $f (x) = t^{2} + t - 2$ $f (t) = (t + 2) (t - 1)$

from the graph it is many-one and into.

Stream:JEESubject:MathematicsTopic:FunctionsSubtopic:General (Definition,type and special type)

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