If the range of f ( x ) = 2 + 3 x , − 3 ≤ x < − 1 is [ 0 , 3 n ] where n ∈ N then n =

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If the range of $f (x) = 2 + 3 x, - 3 \leq x < - 1$ is $[0, 3 n]$ where $n \in N$ then $n =$

Answer:

Solution:

The given function has local maximum at $x = - 1$ , minimum at $x = 0$ and $F (0) = 0, F (- 1) = 1$ , $F (- 3) = 2 - 33 f (2) = 2^{\frac{2}{3}} = 34$

$∴ range of f (x) = [0, 34]$

Stream:JEESubject:MathematicsTopic:FunctionsSubtopic:Domain-Range

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