If f : R → R is defined by f ( x ) = 1 + [ x ] 2 s i n [ x ] π + t a n [ x ] π , then the range of f = (where [ x ] denotes integral part of x)

[ x ] = n ∈ Z ⇔ sin [ x ] π = tan [ x ] π = 0

Start Free Mock LoginAlready registered? Login here

Mathematics - Functions Question with Solution | TestHub

MathematicsFunctionsDomain-RangeEasy2 minQB

MathematicsEasysingle choice

If $f : R \to R$ is defined by $f (x) = \frac{s i n [ x ] π + t a n [ x ] π}{1 + [ x ] ^{2}}$ , then the range of $f =$ (where $[x]$ denotes integral part of x)

Options:

Answer:

Solution:

$[x] = n \in Z \Leftrightarrow sin [x] π = tan [x] π = 0$

Stream:JEESubject:MathematicsTopic:FunctionsSubtopic:Domain-Range

⏱ 2mℹ️ Source: QB

Doubts & Discussion

Loading discussions...